OCOTP: Update OCOTP driver to support i.MX6SLL
Add the i.MX6SLL support to OCOTP driver. The i.MX6SLL reuses the i.MX6ULL fuse, bank 7 and bank8 have 4 words each, and there is a hole between bank 5 and bank 6. Signed-off-by: Ye Li <ye.li@nxp.com> Signed-off-by: Peng Fan <peng.fan@nxp.com>
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0114011986
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b2ebdd85d9
1 changed files with 8 additions and 8 deletions
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@ -62,7 +62,7 @@
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#define FUSE_BANK_SIZE 0x80
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#ifdef CONFIG_MX6SL
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#define FUSE_BANKS 8
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#elif defined(CONFIG_MX6ULL)
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#elif defined(CONFIG_MX6ULL) || defined(CONFIG_MX6SLL)
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#define FUSE_BANKS 9
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#else
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#define FUSE_BANKS 16
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@ -79,7 +79,7 @@
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/*
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* There is a hole in shadow registers address map of size 0x100
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* between bank 5 and bank 6 on iMX6QP, iMX6DQ, iMX6SDL, iMX6SX,
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* iMX6UL and i.MX6ULL.
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* iMX6UL, i.MX6ULL and i.MX6SLL.
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* Bank 5 ends at 0x6F0 and Bank 6 starts at 0x800. When reading the fuses,
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* we should account for this hole in address space.
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*
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@ -100,8 +100,8 @@ u32 fuse_bank_physical(int index)
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if (is_mx6sl()) {
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phy_index = index;
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} else if (is_mx6ul() || is_mx6ull()) {
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if (is_mx6ull() && index == 8)
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} else if (is_mx6ul() || is_mx6ull() || is_mx6sll()) {
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if ((is_mx6ull() || is_mx6sll()) && index == 8)
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index = 7;
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if (index >= 6)
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@ -121,7 +121,7 @@ u32 fuse_bank_physical(int index)
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u32 fuse_word_physical(u32 bank, u32 word_index)
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{
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if (is_mx6ull()) {
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if (is_mx6ull() || is_mx6sll()) {
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if (bank == 8)
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word_index = word_index + 4;
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}
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@ -164,10 +164,10 @@ static int prepare_access(struct ocotp_regs **regs, u32 bank, u32 word,
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return -EINVAL;
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}
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if (is_mx6ull()) {
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if (is_mx6ull() || is_mx6sll()) {
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if ((bank == 7 || bank == 8) &&
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word >= ARRAY_SIZE((*regs)->bank[0].fuse_regs) >> 3) {
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printf("mxc_ocotp %s(): Invalid argument on 6ULL\n", caller);
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printf("mxc_ocotp %s(): Invalid argument\n", caller);
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return -EINVAL;
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}
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}
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@ -271,7 +271,7 @@ static void setup_direct_access(struct ocotp_regs *regs, u32 bank, u32 word,
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#else
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u32 addr;
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/* Bank 7 and Bank 8 only supports 4 words each for i.MX6ULL */
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if ((is_mx6ull()) && (bank > 7)) {
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if ((is_mx6ull() || is_mx6sll()) && (bank > 7)) {
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bank = bank - 1;
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word += 4;
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}
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