python3: fix distutils path to package when using bytecodes
If there is only Python bytecodes, then the __init__.py script will be concatenated, and the __init__.pyc as well. This is becase this bit `path = os.path.join(path, '__init__'+extension)` is iterated twice. This is a bug in Python3, also because we ship bytecodes instead of source code [ with Python & Python3 ]. Python is not affected. Reported-by: Mirko Vogt <mirko@nanl.de> Signed-off-by: Alexandru Ardelean <ardeleanalex@gmail.com>
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2 changed files with 17 additions and 1 deletions
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@ -14,7 +14,7 @@ PYTHON_VERSION:=$(PYTHON3_VERSION)
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PYTHON_VERSION_MICRO:=$(PYTHON3_VERSION_MICRO)
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PKG_NAME:=python3
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PKG_RELEASE:=2
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PKG_RELEASE:=3
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PKG_VERSION:=$(PYTHON_VERSION).$(PYTHON_VERSION_MICRO)
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PKG_SOURCE:=Python-$(PKG_VERSION).tar.xz
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@ -0,0 +1,16 @@
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diff --git a/Lib/imp.py b/Lib/imp.py
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index 781ff23..beeac70 100644
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--- a/Lib/imp.py
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+++ b/Lib/imp.py
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@@ -203,8 +203,9 @@ def load_package(name, path):
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extensions = (machinery.SOURCE_SUFFIXES[:] +
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machinery.BYTECODE_SUFFIXES[:])
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for extension in extensions:
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- path = os.path.join(path, '__init__'+extension)
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- if os.path.exists(path):
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+ init_path = os.path.join(path, '__init__'+extension)
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+ if os.path.exists(init_path):
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+ path = init_path
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break
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else:
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raise ValueError('{!r} is not a package'.format(path))
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