python3: fix distutils path to package when using bytecodes

If there is only Python bytecodes, then
the __init__.py script will be concatenated, and
the __init__.pyc as well.

This is becase this bit `path = os.path.join(path, '__init__'+extension)`
is iterated twice.

This is a bug in Python3, also because we ship bytecodes
instead of source code [ with Python & Python3 ].
Python is not affected.

Reported-by: Mirko Vogt <mirko@nanl.de>
Signed-off-by: Alexandru Ardelean <ardeleanalex@gmail.com>
This commit is contained in:
Alexandru Ardelean 2017-06-12 23:17:05 +03:00
parent 3c820ff9ad
commit 576c45eb0a
2 changed files with 17 additions and 1 deletions

View file

@ -14,7 +14,7 @@ PYTHON_VERSION:=$(PYTHON3_VERSION)
PYTHON_VERSION_MICRO:=$(PYTHON3_VERSION_MICRO)
PKG_NAME:=python3
PKG_RELEASE:=2
PKG_RELEASE:=3
PKG_VERSION:=$(PYTHON_VERSION).$(PYTHON_VERSION_MICRO)
PKG_SOURCE:=Python-$(PKG_VERSION).tar.xz

View file

@ -0,0 +1,16 @@
diff --git a/Lib/imp.py b/Lib/imp.py
index 781ff23..beeac70 100644
--- a/Lib/imp.py
+++ b/Lib/imp.py
@@ -203,8 +203,9 @@ def load_package(name, path):
extensions = (machinery.SOURCE_SUFFIXES[:] +
machinery.BYTECODE_SUFFIXES[:])
for extension in extensions:
- path = os.path.join(path, '__init__'+extension)
- if os.path.exists(path):
+ init_path = os.path.join(path, '__init__'+extension)
+ if os.path.exists(init_path):
+ path = init_path
break
else:
raise ValueError('{!r} is not a package'.format(path))