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luci-base: ui.js: hide unsatisfied firstchild menu nodes

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Signed-off-by: Jo-Philipp Wich <jo@mein.io>
This commit is contained in:
Jo-Philipp Wich 2020-04-18 23:05:01 +02:00
parent 2dbd9ff245
commit 7882f3ebdd
1 changed files with 22 additions and 1 deletions
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23
modules/luci-base/htdocs/luci-static/resources/ui.js
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@ -2944,6 +2944,27 @@ var UIFileUpload = UIElement.extend(/** @lends LuCI.ui.FileUpload.prototype */ {
}
});
function scrubMenu(node) {
var hasSatisfiedChild = false;
if (L.isObject(node.children)) {
for (var k in node.children) {
var child = scrubMenu(node.children[k]);
if (child.title)
hasSatisfiedChild = hasSatisfiedChild || child.satisfied;
}
}
if (L.isObject(node.action) &&
node.action.type == 'firstchild' &&
hasSatisfiedChild == false)
node.satisfied = false;
return node;
};
/**
* Handle menu.
*
@ -2979,7 +3000,7 @@ var UIMenu = baseclass.singleton(/** @lends LuCI.ui.menu.prototype */ {
if (!L.isObject(this.menu)) {
this.menu = request.get(L.url('admin/menu')).then(L.bind(function(menu) {
this.menu = menu.json();
this.menu = scrubMenu(menu.json());
session.setLocalData('menu', this.menu);
return this.menu;